The width of the rectangle is 7 cm, which is 7/9 of its length. Calculate the perimeter and area of the given rectangle.

1) What is the length of the rectangle if it is known from the problem statement that the width of the rectangle is 7 cm, which is 7/9 of its length?

7: (7/9) = 7 ∙ (9/7) = 9 (cm).

2) What is the perimeter of a given rectangle if the perimeter of an arbitrary rectangle is found as the doubled sum of the length and width?

2 ∙ (7 + 9) = 2 ∙ 16 = 32 (cm).

3) What is the area of ​​a given rectangle if the area of ​​an arbitrary rectangle is found as the product of length and width?

9 ∙ 7 = 63 (cm²).

Answer: The perimeter of this rectangle is 32 cm, and the area of ​​this rectangle is 63 cm².