The width of the rectangle is 7cm, and the length is 2cm more. Find the perimeter and area of the rectangle.

The width of the rectangle is 7cm, and the length is 2cm more. Find the perimeter and area of the rectangle. Find the area of a square that has the same perimeter.

Find the perimeter and area of a rectangle whose opposite sides are equal, provided that its width is 7 cm and its length is 2 cm longer (7 + 2 = 9 cm).
P = 2a + 2b = 2 * 9 + 2 * 7 = 18 + 14 = 32 cm.

S = a * b = 9 * 7 = 63 cm².

Let’s calculate the area of a square whose perimeter is 32 cm.
Since the measurements of such a figure are equal: P = 4a.

Let us express the side, for this we divide the product by the first factor:

a = P: 4 = 32: 4 = 8 cm.

S = a² = 8 * 8 = 64 cm².