The width of the rectangle is 8 decimetres, which is one third of its length. Find the perimeter and area of the rectangle.
The solution of the problem.
1) Find the length of the rectangle:
8 * 3 = 24 dm.
2) Find the perimeter of the rectangle, that is, the sum of the lengths of all its sides:
P = 8 + 8 + 24 +24 = 16 + 48 = 64 dm.
3) Find the area of the rectangle, that is, the product of its length and width:
S = 8 * 24 = 192 dm ^ 2.
Answer: 64 dm; 192 dm ^ 2.
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