The width of the rectangle is 8 dm, this is 4 times less than its length. Find the perimeter and area of this rectangle?

In order to find the area and perimeter of a rectangle, you need to know all of its measurements.

We know that the width is 8 dm, and the length, according to the condition, is 4 times greater. Let’s find it:

8 * 4 = 32 dm.

The sum of all sides of such a figure, the opposite dimensions of which are equal, is calculated by the formula:

P = 2a + 2b = 2 * 32 + 2 * 8 = 64 + 16 = 80 dm.

Let’s calculate the area using the formula:

S = a * b = 32 * 8 = 256 dm².