The width of the rectangle is 8 dm, which is 1.3 of its length. find the perimeter and area of a rectangle?

To solve this problem, you first need to find the length of the figure.

Since we know that the width is 1/3 of its part, to determine it, we divide 8 dm by 1/3.

We get:

8 / 1/3 = 8 * 3/1 = 24 dm.

The perimeter is the sum of all sides of the figure and will be equal to:

24 + 24 + 8 + 8 = 48 + 16 = 64 dm.

It can also be found as follows:

2 * (24 + 8) = 2 * 32 = 64 dm.

The area is the product of the length of the rectangle by its width, so it will be:

24 * 8 = 192 dm2

Answer: Perimeter 64 dm, area 192 dm2