The width of the rectangle is 8 dm, which is 1/3 of its length. Find the perimeter and area of the rectangle.

Let’s find the length of the given rectangle.
Let us denote it by x.
According to the condition of the problem, the width of this rectangle is 8 dm, which is 1/3 of the length of this rectangle, therefore, we can draw up the following equation:
(1/3) * x = 8.
We solve the resulting equation and find the length of this rectangle:
x / 3 = 8;
x = 8 * 3;
x = 24 dm.
Find the perimeter p of a given rectangle as the doubled sum of the length and width of this rectangle:
p = 2 * (24 + 8) = 2 * 32 = 64 dm.
Find the area S of a given rectangle as the product of the length and width of a given rectangle:
S = 24 * 8 = 192 dm².

Answer: the perimeter of this rectangle is 64 dm², the area of ​​this rectangle is 192 dm².