The width of the rectangle is 8 dm, which is 1/3 of the length. Find the perimeter and area of the rectangle.

A rectangle is a rectangle whose opposite sides are equal and parallel. The side of the rectangle that is longer is called the length and is denoted by the letter a, and the side that is shorter is called the width and is denoted by the letter b.

The perimeter of any polygon is equal to the sum of the lengths of all its sides, then the perimeter of the rectangle is:

P = a + a + b + b = 2 * a + 2 * b = 2 * (a + b).

The area of ​​the rectangle is:

S = a * b.

Let’s find the length of the rectangle:
1/3 * a = 8;

a = 8: 1/3;

a = 8 * 3/1;

a = (8 * 3) / 1;

a = 24/1;

a = 24 dm.

Find the perimeter of the rectangle:
P = 2 * (24 + 8);

P = 2 * 32;

P = 64 dm.

Find the area of ​​the rectangle:
S = 24 * 8;

S = 192 dm².

Answer: S = 192 dm²; P = 64 dm.