The width of the rectangle is 8 dm, which is 1 m 2 dm less than the length. Find the perimeter of this rectangle.

1. Let’s find the length of the rectangle if it is known that it is 1 m 2 dm greater than its width:
8 dm + 1 m 2 dm = 1 m 10 dm = 2 m.
2. Find the perimeter of the rectangle by the formula P = 2 * (a + b), where P is the perimeter of a rectangle with length a, width b:
P = 2 * (8 dm + 2 m) = 2 * (8 dm + 20 dm) = 2 * 28 dm = 56 dm.
Answer: the perimeter of the rectangle is 56 dm.