The width of the rectangle is 8 inches, which is 1/3 of its length. Find the perimeter and area of the rectangle.

univerkov | February 1, 2021 | education

Rectangle length (a) =? dm;

The width of the rectangle (b) = 8 dm, which is 1/3 of a;

Perimeter (Ppr.) -? dm;

Area (Sp.) -? dm.

Because by condition, the width of the given rectangle is 1/3 of its length, which means that the length itself is equal to:

b = 8 * 3 = 24 (dm) – is the length of the rectangle.

It is known that the perimeter of a rectangle is found by the following formula: Ppr. = (a + b) * 2.

Substituting the known values of the length and width into this formula, we get:

Ppr. = (a + b) * 2 = (24 + 8) * 2 = 32 * 2 = 64 (dm).

The formula for finding the area of a rectangle: Sppr. = a * b.

Substitute the length and width into this formula and get:

Sp. = a * b = 24 * 8 = 192 (dm ^ 2).

Answer: the perimeter of the rectangle is 64 dm, and its area is 192 dm ^ 2.

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