The width of the rectangle is 8dm, which is one third of its length. find the perimeter and area of the rectangle.

We know that the width of the rectangle is 8 dm, which is one third of its length. First, we need to find its length. To do this, divide the width by 1/3.

1) 8: 1/3 = 8 * 3/1 = 24 decimetres – the length of the rectangle.

We know the length and width of the figure. Now we can find the perimeter and area of the rectangle.

The perimeter of a rectangle is the sum of all its sides.

P = 24 + 24 + 8 + 8 or 24 * 2 + 8 * 2.

The perimeter is 44 decimetres.

Let’s find the area. S = a * b.

S = 24 * 8 = 192 square dm.