The width of the rectangle is 8m. This is 3 times less than the length. Find the perimeter and area of the rectangle.

1. If, according to the condition of the problem, the width of the rectangle is 8 m and it is 3 times less than the length, then the length is 8 * 3 = 24 m.

2. The perimeter of the rectangle is equal to the sum of the lengths of all its four sides, and the opposite sides of the rectangle are equal to each other, which means that the perimeter is 8 + 8 + 24 + 24 = 64 m.

3. The area of a rectangle is equal to the product of its length and width, that is, 8 * 24 = 192 m2.