The width of the rectangle is 9 cm and the length is 6dm more find the area of the square

The width of the rectangle is 9 cm and the length is 6dm more find the area of the square available the same perimeter as this rectangle.

To complete this task, we must first calculate what the length is, knowing that it is 6 decimeters more than the width, equal to 9 cm.

9 + 6 = 15 cm.

Let’s calculate what the perimeter of such a rectangle is.

P = 2 * (9 + 15) = 2 * 24 = 48 cm.

We calculate what the length of the side of a square is equal to, whose perimeter is 48 cm.

a = 48/4 = 12cm.

Let’s calculate what the area of a square with a side of 12 cm is equal to. To do this, we must raise this number to the second power.

S = 12 * 12 = 144 cm².

Answer: 144 cm².