The width of the rectangle is three times less than the length. Find its sides if its area is 48 cm ^ 2.

Let the width of the rectangle be “x” cm. Then the length of the rectangle is equal to “3x” cm.

The area of the rectangle is calculated by the formula:

S = a * b,
where S is the area, a is the length, b is the width.

Knowing that the area of the rectangle is 48 sq. Cm, we will compose the equation:

3x * x = 48;

3x ^ 2 = 48;

3x ^ 2 – 48 = 0;

D = b ^ 2 – 4ac = 0 ^ 2 – 4 * 3 * (−48) = 0 + 576 = 576;

x (1,2) = (−b ± √D) / 2a;

√D = √576 = 24;

x1 = (−0 + 24) / (2 * 3) = 24/6 = 4.

x2 = (−0 – 24) / (2 * 3) = −24/6 = −4.

width = 4 cm.

length = 3x = 3 * 4 = 12 cm.