The wire can withstand a weight of 80 kg suspended from it. What is the mass of the load that can be lifted

The wire can withstand a weight of 80 kg suspended from it. What is the mass of the load that can be lifted with this wire with an acceleration of 3m / s

m times = 80 kg.
a = 3 m / s ^ 2.
g = 9.8 m / s ^ 2.
mmax -?
Let us find the maximum force Fmax that the wire can withstand at rest using the formula: Fmax = m times * g.
Let us write Newton’s 2 law for a body when moving up: mmax * a = Fmax – mmax * g.
When lifting a load with acceleration upwards, the load acts on the wire with a force: Fmax = mmax * (g + a).
mraz * g = mmak * (g + a).
mmak = mraz * g / (g + a).
mmac = 80 kg * 9.8 m / s ^ 2 / (9.8 m / s ^ 2 + 3 m / s ^ 2) = 61.25 kg.
Answer: you can lift up a load weighing no more than mmak = 61.25 kg.