# The wooden ball floats in the water, submerged by one third. In another liquid

**The wooden ball floats in the water, submerged by one third. In another liquid, he immerses twice as much. how much of the ball will float in the mixture.**

1. Find out what part of the ball is immersed in water in percentage = (1/3) * 100% = 33.3%.

2. Find out what part of the ball is immersed in another liquid in percentage = 33.3% * 2 = 66.6%.

3. Knowing that, according to the physical law, the surface tension of a mixture of liquids is equal to the arithmetic mean of the sum of the surface tension of each individual liquid, we determine which part of the ball is immersed in a mixture of water with another liquid. To do this, we sum the values of the immersion of the ball in each of the two liquids in percent and divide the resulting value by the amount of liquids in the mixture = (33.3% + 66.6%) / 2 = 99.9% / 2 = 49.95%, which gives 50% of the ball when rounded.

So, in a mixture of two liquids, 50% of the ball will float.