The work A = 260J was performed on the system, and the amount of heat Q = 320J was transferred to the system.
| December 2, 2020 | education
The work A = 260J was performed on the system, and the amount of heat Q = 320J was transferred to the system. Find the change in the internal energy of the delta U system.
Given:
A = 260 J
Q = 320 J
Find: ∆U =?
Decision:
The work was performed by external forces, which means according to the first law of thermodynamics:
Q = ∆U-A
∆U = Q + A
∆U = 320 J + 260 J = 580
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