The work function of electrons from the zinc surface is 4 Volt electrons. What is the speed of an electron emitted

The work function of electrons from the zinc surface is 4 Volt electrons. What is the speed of an electron emitted from the zinc surface when illuminated by its radiation with a wavelength of 200 nm.

To determine the velocities of the considered electrons emitted from the zinc surface, we use the equality: h * C / λ = Eph = me * V ^ 2/2 + Avykh, whence we express: V = √ (2 * (h * C / λ – Avykh) / me).

Variables and constants: h (Planck’s constant) = 6.626 * 10 ^ -34 J * s; С (speed of propagation of light) ≈ 3 * 10 ^ 8 m / s; λ is the wavelength of the considered electrons (λ = 200 nm = 2 * 10 ^ -7 m); Avykh – work function (Avykh = 4 eV = 6.409 * 10 ^ -19 J); me is the mass of an electron (me = 9.11 * 10 ^ -31 kg).

Calculation: V = √ (2 * (6.626 * 10 ^ -34 * 3 * 10 ^ 8 / (2 * 10 ^ -7) – 6.409 * 10 ^ -19) / (9.11 * 10 ^ -31)) = 880 325 m / s.

Answer: The speed of the outgoing electrons, according to the calculation, is equal to 880 325 m / s.



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