The work of the elastic force is 700J, the length of the spring has changed by 2.5 cm. What is the stiffness of the spring.
| November 21, 2020 | education
A = 700 J.
x = 2.5cm = 0.025m.
A = F * S;
Hence: F = A / S = 700 / 0.025 = 28000H;
F = kx;
k = F / x = 28000 / 0.025 = 1120000H / m ^ 2
Answer: k = 1120000H / m ^ 2
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