The work of the elastic force when the spring is stretched by 2 cm with an elastic coefficient of 40N / m is equal to?

To calculate the required work of the elastic force, we use the formula: A = k * (x2 ^ 2 – x1 ^ 2) / 2 = k * Δx ^ 2/2.

Values of variables: k – coefficient of elasticity (k = 40 N / m); Δx – spring deformation (Δx = 2 cm = 0.02 m).

Let’s make a calculation: A = k * Δx ^ 2/2 = 40 * 0.02 ^ 2/2 = 0.008 J or 8 mJ.

Answer: The sought elastic force work is 8 mJ.