The worker lifts a load weighing 1100kg to a height of 0.4m using a lever. A force of 900H is applied

| May 6, 2021 | education

The worker lifts a load weighing 1100kg to a height of 0.4m using a lever. A force of 900H is applied to the larger arm of the lever under the action of which the end of the lever is lowered by 0.6 m. Determine the efficiency of the lever.

Task data: m (mass of the lifted working load) = 110 kg; h1 (lifting height) = 0.4 m; F (force applied to the larger arm) = 900 N; h2 (the height to which the larger shoulder sank) = 0.6 m.

Reference values: g (acceleration due to gravity) = 9.81 m / s2.

The efficiency of the lever used by the worker can be calculated by the formula: η = Ap / Az = P * h1 / (F * h2) = m * g * h1 / (F * h2).

Let’s perform the calculation: η = 110 * 9.81 * 0.4 / (900 * 0.6) = 0.8 (80%).

Answer: The efficiency of the used lever is 80%.



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