The worker must lift a weight of 96 kg using a mobile unit with an efficiency of 80%. Determine the amount of traction that must be applied for this.
Initial data: η (efficiency of the mobile unit) = 80% (0.8); m (mass of the load being lifted) = 96 kg.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
The traction force, which was applied to lift the load with the help of the movable block, is determined from the formula: η = Ap. / Az. = Ep / (F * S) = m * g * h / (Ft * 2h) = m * g / 2F and Ft = m * g / 2η.
Let’s calculate: Ft = 96 * 10 / (2 * 0.8) = 600 N.
Answer: To lift the load, a traction force of 600 N was applied to the movable block.
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