The worker with the help of a movable block lifted the load to a height of 5m, applying
| August 6, 2021 | education
The worker with the help of a movable block lifted the load to a height of 5m, applying a force of 160 N to the free end of the rope. What work did he do?
Data: moving block; h (lifting height) = 5 m; F (force applied to the rope) = 160 N.
To calculate the perfect work of the worker in question, we will use the formula: A = P * S = 2 * F * h.
Calculation: A = 2 * 160 * 5 = 1.6 * 10 ^ 3 J (1.6 kJ).
Answer: the work done by the worker in question is 1.6 kJ.
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