The working body of the heat engine received 50 kJ from the heater and transferred 25 kJ of heat
| September 9, 2021 | education
The working body of the heat engine received 50 kJ from the heater and transferred 25 kJ of heat to the refrigerator. Determine the efficiency of the heat engine.
These tasks: Qн (the amount of heat that the taken working fluid received from the heater) = 50 kJ; Qx (the heat that the taken working fluid transferred to the refrigerator) = 25 kJ.
To determine the CDP of a given heat engine, we use the formula: η = (Qн – Qх) / Qн.
Let’s calculate: η = (50 – 25) / 50 = 0.5 or 50%.
Answer: The efficiency of a given heat engine is 50%.
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