The zinc was affected by 50 g of a 24.5% sulfuric acid solution. Calculate the amount of gas released.

univerkov | December 8, 2020 | education

m (Zn) = 50 grams
w (H2SO4) = 24.5%
Find: V (H2) =?
Decision:
Zn + H2SO3 = ZnSO4 + H2
m (H2SO4) = 0.245 * 50 = 12.25 grams
n (H2SO4) = 12.25 / 98 = 0.125 mol
n (H2SO4) = n (H2) = 0.125 mol
V (H2) = n * Vm = 0.125 * 29.4 = 3.675 liters
Answer: 3.675 liters

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