There are 10 single desks in the classroom. In many ways you can seat three schoolchildren on them.

Let’s find in how many ways you can seat three schoolchildren on ten desks:

C3 / 10 = 10! / (3! * (10-3)!) = 240.

The classical problem of combinatorics is the problem of the number of combinations without repetitions.

Answer: Three students can be seated in 240 ways on 10 desks.



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