There are 12 liters of carbon dioxide at a pressure of 9 • 10 ^ 5 Pa and a temperature of 288 K. Find the mass of gas.

P * V = (m / M) * R * T, where P is the gas pressure (P = 9 * 105 Pa), V is the gas volume (V = 12 l = 12 dm3 = 0.012 m3), m is the sought gas mass , M is the molar mass of carbon dioxide (M = 44 g / mol = 0.044 kg / mol), R is the universal gas constant (R = 8.31 J / (mol * K)), T is the absolute temperature (T = 288 K) …

Let’s calculate the mass of gas:

R * V = m * R * T / M.

m = M * R * V / (R * T) = 0.044 * 9 * 105 * 0.012 / (8.31 * 288) = 0.199 kg = 199 g.

Answer: The mass of carbon dioxide is 199 g.