There are 12 liters of carbon dioxide at a pressure of 9 • 10 ^ 5 Pa and a temperature of 288 K. Find the mass of gas.

P * V = (m / M) * R * T, where P is the gas pressure (P = 9 * 10 ^ 5 Pa), V is the gas volume (V = 12 l = 12 dm3 = 0.012 m3), m is the desired gas mass, M – molar mass of carbon dioxide (M = 44 g / mol = 0.044 kg / mol), R – universal gas constant (R = 8.31 J / (mol * K)), T – absolute temperature (T = 288 K).

Let’s calculate the gas mass:

R * V = m * R * T / M.

m = M * P * V / (R * T) = 0.044 * 9 * 10 ^ 5 * 0.012 / (8.31 * 288) = 0.199 kg = 199 g.

Answer: The mass of carbon dioxide is 199 g.



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