There are 2 black and 10 white balls in the urn. 2 balls were taken out at random. What is the probability

There are 2 black and 10 white balls in the urn. 2 balls were taken out at random. What is the probability that: a) both balls are black b) both balls are white c) one is white, the second is black

To solve the problem, we will use the probability formula: Р = m / n, where m are all the necessary events, and n are all possible events.

The problem says that there are 2 black and 10 white balls in the urn, where the probability that both balls are black: 2/12 * 1/11 = 1/66 = 0.02 or 2%.

Then the probability that both balls are white: 10/12 * 9/11 = 15/22 = 0.68 or 68%.

And the probability that one white second is black: equal to 10/12 * 2/11 = 5/33 = 0.15 or 15%.