There are 2 forces acting on the lever. The force acting on a short arm with a length of 0.1 m is 3N

| May 7, 2021 | education

There are 2 forces acting on the lever. The force acting on a short arm with a length of 0.1 m is 3N. What should be the length of the second arm, on which a force of 1N acts, for the lever to be in balance?

L1 = 0.1 m.

F1 = 3 N.

F2 = 1 N.

L2 -?

When the lever is in equilibrium, the moments of forces that act from opposite sides of the lever are equal to each other: M1 = M2.

The moment of force M is the product of the applied force F to the smallest distance from the line of action of the force to the axis of rotation of the lever L: M = F * L.

The smallest distance from the line of action of the force F to the axis of rotation of the lever is called its arm L.

F1 * L1 = F2 * L2.

The length of the second arm will be determined by the formula: L2 = F1 * L1 / F2.

L2 = 3 N * 0.1 m / 1 N = 0.3 m.

Answer: In balance, the larger lever arm is L2 = 0.3 m.



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