There are 20 g of oxygen in a 10 liter vessel at a pressure of 2 atm. Find the gas temperature.

To find out the temperature of oxygen in the indicated vessel, we use the formula: P * V = m * R * T / MO2, from where we express: T = MO2 * P * V / (m * R).

Const: MO2 – molar mass of oxygen (MO2 = 32 g / mol); R – universal gas constant (R = 8.31 J / (mol * K)).

Data: P – oxygen pressure (P = 2 atm. = 2 * 101325 Pa); V is the volume of the vessel (V = 10 l = 0.01 m3); m is the mass of oxygen (m = 20 g).

Let’s calculate: T = MO2 * P * V / (m * R) = 32 * 2 * 101325 * 0.01 / (20 * 8.31) = 390.18 K or 117.03 ºС.

Answer: The oxygen temperature in the indicated vessel should be 390.18 K.