There are 20 tickets in the box with a win and 15 tickets without a win. squeeze

There are 20 tickets in the box with a win and 15 tickets without a win. squeeze out two tickets one after the other (no refund). find the probability that both winning tickets

Let’s find the total number of tickets in the urn:
20 + 15 = 35 tickets
Let us find the probability of taking out 2 winning tickets using the hypergeometric probability formula.
The number of ways to take out 2 tickets out of 35:
C (35,2) = 35! / (2! (35 – 2)!) = 35 34/2 = 595;
The number of ways to take out 2 tickets out of 20 winning ones:
C (20.2) = 20! / (2! (20 – 2)!) = 20 19/2 = 190;
The number of ways to take out 0 tickets out of 15 without winning is:
C (15.0) = 15! / (0! (15 – 0)!) = 1;
The likelihood that both won tickets are taken out:
P (A) = C (20.2) C (15.0) / C (35.2) = 190 1/595 = 0.3193.
Answer: The probability that both winning tickets are 0.3193.



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