# There are 3 balls in the urn: 2 white and 1 black. The event is that one ball is taken out of the urn.

**There are 3 balls in the urn: 2 white and 1 black. The event is that one ball is taken out of the urn. Answer the questions: a) how many opportunities are there; b) how many opportunities there are to remove the white ball; c) how many possibilities are there to remove the black ball; d) what is the probability that the removed ball will be white; e) what is the probability that the removed ball will be black.**

a) There are three possibilities to take out ANY ball because we have only 3 balls.

b) There are two possibilities to take out the white ball, again because we have only 2 white balls.

c) Remove the black ball, by analogy with the previous question, we have 1 opportunity.

d) The white ball is taken out with a probability of 2/3, since in general we have 3 balls, and white ones 2, and it follows that the ability to take out the white ball 2 out of 3, problems of this type are solved by formula P (A) = m / n, where m is the number of favorable outcomes we need, and n is the number of all possible outcomes (explanation that this is in point b).

e) By analogy, we solve and it turns out 1/3, since, using the formula P (A) = m / n, we understand that the loss of the black ball is a favorable outcome.