There are 4 white and 7 black balls in the urn, 2 balls are taken out of the urn at the same time

There are 4 white and 7 black balls in the urn, 2 balls are taken out of the urn at the same time, what is the probability that both balls are white.

There are 4 + 7 = 11 balls in the urn.
The total number of outcomes when taking two balls out of 11:
n = C (11,2) = 11! / (2! (11 – 2)!) = 10 11 / (1 2) = 55.
The number of outcomes when removing 2 white balls out of 4:
C (4,2) = 4! / (2! (4 – 2)!) = 3 4 / (1 2) = 6.
The number of ways to remove zero black balls out of 7:
C (7.0) = 1.
Number of favorable options:
m = C (4.2) C (7.0) = 6 1 = 6.
The probability that both balls taken out are white.
P = m / n = 6/55 = 0.109.
Answer: 0.109.