There are 735 g of a 16% solution of iodine in alcohol. How much should be added to the existing

There are 735 g of a 16% solution of iodine in alcohol. How much should be added to the existing alcohol solution to get a 10% solution.

Since the solution contains 16% iodine, then in 735 grams of solution the amount of iodine will be equal to:

735: 100 * 16 = 117.6 (g).

Let’s say that to get a 10% solution, you need to add x gram of alcohol. Then, according to the condition of the problem, we can compose the following equation:

117.6: (735 + x) = 10: 100,

117.6 = (735 + x) * 0.1,

117.6 = 73.5 + 0.1 * x,

0.1 * x = 117.6 – 73.5,

0.1 * x = 44.1,

x = 44.1: 0.1,

x = 441 (g).

Answer: 441 grams.