There are three pipes in the pool. With the help of the first, it can be filled at 10 am, with the help

| June 17, 2021 | education

There are three pipes in the pool. With the help of the first, it can be filled at 10 am, with the help of the second 8 hours, with the help of the third, all the water from the filled pool can pour out in 5 hours. Determine the profit of water in the pool after each hour of joint action of all three pipes.

If through the first pipe the pool is collected in 10 hours, then in 1 hour, through it, 1/10 of the pool will be collected.

If through the second pipe the pool is collected in 8 hours, then in 1 hour, through it, 1/8 of the pool will be collected.

If in five hours all the water from the pool flows out through the third pipe, then in 1 hour 1/5 of the volume of water will flow out.

To determine the increase in water for each hour, with all pipes open, it is necessary to add the volumes of water flow from the first two pipes, and subtract the volume of water flowing out from the third pipe.

X = 1/10 + 1/8 – 1/5 = (4 + 5 – 8) / 40 = 1/40.

Answer: With three pipes open, the increase in water in the pool for every hour will be 1/40 of the volume of the pool. The entire pool will be filled in 40 hours.



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