There are two alloys available, consisting of zinc, copper and tin. It is known that the first alloy

There are two alloys available, consisting of zinc, copper and tin. It is known that the first alloy contains 40% tin, and the second 26% copper. The percentage of zinc in the first and second alloys is the same. Having melted 150 kg of the first alloy and 250 kg of the second, we got a new alloy, in which 30% zinc turned out. Determine how many kg of tin is contained in the resulting alloy.

1. Mass of the first alloy: M1 = 150 kg;

2. Mass of the second alloy: M2 = 250 kg;

3. The percentage of zinc in alloys: Pz %%;

4. The first alloy contains tin: P1o = 40%;

5. It contains copper: P1m = 100 – (P1m + Pz) = 100 – 40 – Pz = (60 – Pz)%;

6. The second alloy contains copper: P2m = 26%;

7. It contains tin: P2o = 100 – P2m – Pz = 100 – 26 – Pz = (74 – Pz)%;

8. The resulting zinc alloy contains: P3z = 30%;

M3z = (P3z / 100) * M = (30/100) * (150 + 250) = 0.3 * 400 = 120 kg;

M3z = M1z + M2z = (Pz / 100) * M1 + (Pz / 100) * M2 =

(Pz / 100) * (M1 + M2) = (Pz / 100) * M;

Pz = P3z = 30%;

M1z = (Pz / 100) * M1 = 0.3 * 150 = 45 kg;

M2z = (Pz / 100) * M2 = 0.3 * 250 = 75 kg;

9. In the first alloy:

M1o = (P1o / 100) * M1 = 0.4 * 150 = 60 kg;

10. In the second alloy:

M2m = (P2m / 100) * M2 = 0.26 * 250 = 65 kg;

M2o = M2 – M2z – M2m = 250 – 75 – 65 = 110 kg;

11. The resulting alloy contains tin:

M3o = M1o + M2o = 60 + 110 = 170 kg.

Answer: the new alloy contains 170 kg of tin.