There are two ice blocks. The dimensions of the first block are 3   x 3   x 3 dm, the dimensions of the third 4   x 3   x 2 dm.

There are two ice blocks. The dimensions of the first block are 3   x 3   x 3 dm, the dimensions of the third 4   x 3   x 2 dm. The weight of which block is smaller and how much

Given: a1 = 3 dm = 0.3 m b1 = 3 dm = 0.3 m c1 = 3 dm = 0.3 m
a2 = 4 dm = 0.4 m b2 = 3 dm = 0.3 m c2 = 2 dm = 0.2 m
Find: m1 / m2 – ??
Decision:
m = p * V
ice density p = 900 kg / m ^ 3
V = a * b * c
V1 = 0.3 * 0.3 * 0.3 = 0.027 m ^ 3
V2 = 0.4 * 0.3 * 0.2 = 0.024 m ^ 3
m1 = 900 * 0.027 = 24.3 kg
m2 = 900 * 0.024 = 21.3 kg
more by m1 – m2 = 24.3 – 21.3 = 3 kg
more in m1 / m2 = 24.3 / 21.3 = 1.14 times
The mass of the second bar is 3 kg less and 1.14 times less