There are two lead balls. How many times is the mass of the first ball greater than the mass

There are two lead balls. How many times is the mass of the first ball greater than the mass of the second, if 3 times more heat is spent to heat the first ball by 1.5 K than to heat the second by 1 K?

The amount of heat is determined from the following expression:
Q = c * m * (t2-t1)
For the first ball (we have the same c, because the material is the same):
Q1 = c * m1 * (t2-t1) = c * m1 * 1.5
For the second:
Q2 = c * m2 * (t2-t1) = c * m ** 1
Let us express the masses from these expressions:
m1 = Q1 / 1.5 * s
m2 = Q2 / 1 * s
Let’s divide m1 / m2:
m1 / m2 = (Q1 / 1.5 * s) / (Q2 / 1 * s) = Q1 / (1.5 * Q2) = 2
Answer: 2 times.