There is 100 grams of 30% salt solution. 200 grams of water is mixed with it.

There is 100 grams of 30% salt solution. 200 grams of water is mixed with it. What is the concentration of the resulting solution?

1. Determine how many grams of salt was contained in the original solution. We take this mass of salt as a and make up the proportion:

100 g – 100%, and g – 30%;

100: a = 100: 30;

a = (100 x 30): 100;

a = 30 g;

2. Determine what the mass of the new solution has become after adding water to it:

100 + 200 = 300 g;

3. Determine the salt concentration in the newly formed solution. We take this concentration as a and make up the proportion:

300 g – 100%, 30 g – a%;

300: 30 = 100: a;

a = (30 x 100): 300;

a = 10%.

Answer: 10 percent of the salt is in the new solution.