There is 200 grams of a solution with a mass fraction of salt of 10%, determine the mass fraction of salt

There is 200 grams of a solution with a mass fraction of salt of 10%, determine the mass fraction of salt in the solution that is formed when added to the original solution a) 20 grams of salt b) 300 grams of water in 10 grams of water and 10 grams of salt d) 50 grams of salt

Let’s calculate the masses of salt and water in the initial solution:

m1 (salt) = w1 (salt) * m1 (solution) = 0.1 * 200 = 20 g;

m (H2O) = m1 (solution) – m (salts) = 200 – 20 = 180 g;

a) determine the mass fraction after adding 20 g of salt:

m2 (solution) = m1 (solution) + 20 = 220 g;

m2 (salt) = m1 (salt) + 20 = 20 + 20 = 40 g;

w2 (salt) = m2 (salt): m2 (solution) = 40: 220 = 0.1818 or 18.18%;

b) find the proportion of salt when diluting the initial solution with 300 g of water:

m3 (solution) = m1 (solution) + m (H2O) = 200 + 300 = 500 g;

w3 (salt) = m1 (salt): m3 (solution) = 20: 500 = 0.04 or 4%;

c) calculate the proportion of salt after adding portions of water and salt:

m4 (salts) = m1 (salts) + mdob (salts) = 20 + 10 = 30 g;

m4 (solution) = m1 (solution) + mdob (H2O) = 200 + 10 = 210 g;

w4 (salts) = m4 (salts): m4 (solution) = 30: 210 = 0.1429 or 14.29%;

d) calculate the mass fraction after adding 50 g of salt:

m5 (solution) = m1 (solution) + 50 = 200 + 50 = 250 g;

m5 (salts) = m1 (salts) + 50 = 20 + 50 = 70 g;

w5 (salts) = m5 (salts): m5 (solution) = 70: 250 = 0.28 or 28%.

Answer: a) 18.18%, b) 4%, c) 14.29%, d) 28%.