There is 30 kg of an 8% solution of salt in water. How many kg of pure water must be added to this solution to make the salt content equal to 5%?
To solve the problem, we first find the weight of the salt in the initial solution.
To do this, multiply the weight of the solution by the percentage.
30 * 8% / 100% = 30 * 0.08 = 2.4 kg (salt in solution).
We find the required weight of the solution so that the salt content in it is 5%.
To do this, divide the weight of the salt by the desired percentage.
2.4 / (5% / 100%) = 2.4 * 100/5 = 240/5 = 48 kg.
We find the amount of water.
48 – 30 = 18 kg.
To obtain a 5% solution, you need to add 18 kg of water.
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