There is 30 kg of an 8% solution of salt in water. How many kg of pure water must

There is 30 kg of an 8% solution of salt in water. How many kg of pure water must be added to this solution to make the salt content equal to 5%?

To solve the problem, we first find the weight of the salt in the initial solution.

To do this, multiply the weight of the solution by the percentage.

30 * 8% / 100% = 30 * 0.08 = 2.4 kg (salt in solution).

We find the required weight of the solution so that the salt content in it is 5%.

To do this, divide the weight of the salt by the desired percentage.

We get:

2.4 / (5% / 100%) = 2.4 * 100/5 = 240/5 = 48 kg.

We find the amount of water.

48 – 30 = 18 kg.

Answer:

To obtain a 5% solution, you need to add 18 kg of water.