There is a 0.045 chance that a new DVD player will go into warranty repair within a year.

There is a 0.045 chance that a new DVD player will go into warranty repair within a year. In some city out of 1000 sold DVD-players during the year 51 units were delivered to the warranty workshop. How much does the frequency of a “warranty repair” event differ from its likelihood in this city?

In order to determine the frequency of warranty repairs, we must divide the number of returned DVD players by the number of DVD players sold.

51/1000 = 0.051 probability that the DVD player will be sent for warranty repair within a year

We calculate how much the frequency of the “repair guarantees” event differs from its probability in this city:

0.051 – 0.045 = 0.006

Answer: by 0.006 the frequency of an event differs from its probability.



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