There is a bottle of 20% acid solution and a bottle of 40% acid solution a) Mix 200 g of solution from the first bottle

There is a bottle of 20% acid solution and a bottle of 40% acid solution a) Mix 200 g of solution from the first bottle and 300 g from the second. Determine the mass of the acid and its proportion in the resulting solution. b) 300 g of acid solution was taken from the first bottle. How many grams of acid solution must be added from the second bottle to get a 32% acid solution?

We have two solutions with concentrations of 20% and 40%, respectively.

1) Took 200 grams of the first solution and 300 grams of the second solution. Let’s determine the new concentration of the solution.

The mass of the substance in the first solution is:

200 * 0.2 = 40 g.

The mass of the substance in the second solution:

300 * 0.4 = 120 g.

The mass of the substance in the new solution is 120 + 40 = 160 g. The new mass of the solution is 200 + 300 = 500 g.

The concentration is equal to:

160/500 = 0.32 = 32%.

2) 300 g of solution was taken from the first bottle.

The mass of the substance in the first solution is 300 * 0.2 = 60 g.

Let the mass of the second solution be x, the mass of the substance there – 0.4 * x.

We get:

(60 + 0.4 * x) = 0.32 * (x + 300);

60 + 0.4 * x = 0.32 * x + 96;

0.08 * x = 36;

x = 450 g.