There is a charge of 0.2 C on the capacitor rims of the capacitance of the capacitor 10 ^ 4 μF.

There is a charge of 0.2 C on the capacitor rims of the capacitance of the capacitor 10 ^ 4 μF. what is the voltage between capacitor plates?

These tasks: q (charge on the capacitor plates) = 0.2 C; C (indicated electrical capacity of the capacitor) = 10 ^ 4 μF (10 ^ -2 F).

The voltage between the capacitor plates is determined from the formula for calculating its electrical capacity: C = q / U, whence U = q / C.

Calculation: U = 0.2 / 10 ^ -2 = 20 V.

Answer: The voltage between the capacitor plates is 20 V.