There is a copper bar 2 * 5 * 6 cm in size on the weighing pan. Determine the force with which

There is a copper bar 2 * 5 * 6 cm in size on the weighing pan. Determine the force with which the bar acts on the weighing pan?

The force with which a copper bar acts on the weighing pan:

F = Fт = m * g, where m is the mass of a copper bar (m = ρ * V, where ρ is the density of copper (ρ = 8900 kg / m³), V is the volume of a copper bar (V = a * b * c, where a – length of a copper bar (a = 2 cm = 0.02 m), b – width of a copper bar (b = 5 cm = 0.05 m), c – thickness of a copper bar (c = 6 cm = 0.06 m) )), g is the acceleration of gravity (g = 10 m / s2).

F = ρ * a * b * c * g = 8900 * 0.02 * 0.05 * 0.06 * 10 = 5.34 N.

Answer: The force is 5.34 N.



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