There is water in the cistern of the street watering machine. How much will the weight of the machine

There is water in the cistern of the street watering machine. How much will the weight of the machine decrease if it spills 200 liters of water?

To find out the decrease in the weight of the watering machine, we use the formula: ΔР = Δm * g = ρ * ΔV * g, where ρ is the density of water in the watering machine (assumed ρ = 10 ^ 3 kg / m3); ΔV – decrease in the volume of water in the watering machine (ΔV = 200 l = 0.2 m3); g – acceleration due to gravity (const, g ≈ 9.8 m / s2).

Let’s perform the calculation: ΔР = ΔV * ρ * g = 0.2 * 10 ^ 3 * 9.8 = 19.6 * 10 ^ 3 H ≈ 2 kN.

Answer: 2) Reducing the weight of the sprinkler will be 2 kN.