There was 10.05 kg of water in a saucepan at a temperature of 20 degrees. How much fuel would it take

There was 10.05 kg of water in a saucepan at a temperature of 20 degrees. How much fuel would it take to heat this water to a boil? specific heat of water 4200 J / kg degree specific heat of combustion of fuel 3 j / kg boiling point of water 100 degrees

Given: m1 (mass of water in the pan) = 10.05 kg; t (water temperature) = 20 ºС.

Constants: by condition Cw (specific heat capacity of water) = 4200 J / (kg * ºС); q (specific heat of combustion of fuel) = 3 * 107 J / kg; tboil (boiling point of water) = 100 ºС.

The mass of fuel for heating water to boiling is determined from the equality: Sv * m1 * (tboil – t) = q * m2, whence m2 = Sv * m1 * (tboil – t) / q.

Calculation: m2 = 4200 * 10.0 ^ 5 * (100 – 20) / (3 * 10 ^ 7) = 0.11256 kg (112.56 g).

Answer: You will need 112.56 grams of fuel.