There were 2 cans in the rain. The diameters of their necks are equal to 10 cm and 20 cm. After 2 hours, 200 ml of rain

There were 2 cans in the rain. The diameters of their necks are equal to 10 cm and 20 cm. After 2 hours, 200 ml of rain water was collected in the first jar. How much was in the second jar?

d1 = 10 cm = 0.1 m.
d2 = 20 cm = 0.2 m.
V1 = 200 ml = 0.2 * 10 ^ -3 m ^ 3.
t = 2h = 3600 s.
V2 -?
The volume of water V1 in the first can is expressed by the formula: V1 = S1 * v * t. Where S1 is the area of ​​the neck of the first can, v is the flow rate of raindrops, t is the time it takes rain to enter the can.
V2 = S2 * v * t.
The necks of the cans are circular, so the area of ​​the neck is determined by the formula S = P * R ^ 2, where P is the number pi, R is the radius of the neck.
Since R = d / 2, then S = P * d ^ 2/4.
S1 = P * d1 ^ 2/4, S2 = P * d2 ^ 2/4.
V1 = P * d1 ^ 2 * v * t / 4.
v = 4 * V1 / P * d1 ^ 2 * t.
V2 = P * d2 ^ 2 * v * t / 4.
V2 = P * d2 ^ 2 * (4 * V1 / P * d1 ^ 2 * t) * t / 4 = d2 ^ 2 * V1 / d1 ^ 2.
V2 = (0.2 m) ^ 2 * 0.2 * 10 ^ -3 m ^ 3 / (0.1 m) ^ 2 = 0.8 * 10 ^ -3 m ^ 3.
Answer: the second jar will have V2 = 0.8 * 10 ^ -3 m ^ 3 of rainwater.