This line contains the points M (-1; 1) and N (1; 0). Write the equation of this line

Let’s find the coordinates of the vector AP, that is, the coordinates of the vector to which the parallel line is:
MN (1 – (- 1), 0-1)
AP (2, -1)
Let’s use the canonical equation of the line:
(x-x0) / a1 = (y-y0) / a2, where (x0, y0) are the coordinates of the point through which the line passes, and (a1, a2) are the coordinates of the vector to which the line is parallel. So,
(x-1) / 2 = (y-0) / – 1
(x-1) / 2 = -y
x-1 = -2y
x + 2y-1 = 0 – equation of the straight line
Odds: 1.2, – 1