Three conductors of 3 ohms, 6 ohms and 8 ohms are connected in parallel. In the first conductor, 4 kJ

| July 7, 2021 | education

Three conductors of 3 ohms, 6 ohms and 8 ohms are connected in parallel. In the first conductor, 4 kJ of heat is released in 1 hour. What amount of heat is released in 2.5 hours in the second and third conductors?

Task data: R1 (resistance of the first conductor) = 3 Ohm; R2 (resistance of the second conductor) = 6 ohms; R3 (resistance of the third conductor) = 8 ohms; parallel connection; t1 (duration of operation of the first conductor) = 1 h = 3600 s; Q1 (heat on the first conductor) = 4 kJ = 4000 J; t3.2 (duration of operation of the second and third conductors) = 2.5 h = 9000 s.

1) Total voltage: Q1 = U ^ 2 * t1 / R1 and U = √ (R1 * Q1 / t1) = √ (3 * 4000/3600) = 1.826 V.

2) Heat on the second conductor: Q2 = U ^ 2 * t3.2 / R2 = 1.826 ^ 2 * 9000/6 = 5 * 10 ^ 3 J = 5 kJ.

3) Heat on the third conductor: Q3 = U ^ 2 * t3.2 / R3 = 1.826 ^ 2 * 9000/8 = 3.75 * 10 ^ 3 J = 3.75 kJ.

Answer: On the second and third conductors taken, 5 kJ and 3.75 kJ of heat were released, respectively.



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